Optimal. Leaf size=401 \[ -\frac{5 i b c^3 \text{PolyLog}\left (2,-i e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{d^2}+\frac{5 i b c^3 \text{PolyLog}\left (2,i e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{d^2}+\frac{13 b^2 c^3 \text{PolyLog}\left (2,-e^{\sinh ^{-1}(c x)}\right )}{3 d^2}-\frac{13 b^2 c^3 \text{PolyLog}\left (2,e^{\sinh ^{-1}(c x)}\right )}{3 d^2}+\frac{5 i b^2 c^3 \text{PolyLog}\left (3,-i e^{\sinh ^{-1}(c x)}\right )}{d^2}-\frac{5 i b^2 c^3 \text{PolyLog}\left (3,i e^{\sinh ^{-1}(c x)}\right )}{d^2}+\frac{5 c^4 x \left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^2 \left (c^2 x^2+1\right )}+\frac{2 b c^3 \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 \sqrt{c^2 x^2+1}}+\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x \left (c^2 x^2+1\right )}-\frac{b c \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 x^2 \sqrt{c^2 x^2+1}}-\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x^3 \left (c^2 x^2+1\right )}+\frac{5 c^3 \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )^2}{d^2}+\frac{26 b c^3 \tanh ^{-1}\left (e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2}-\frac{b^2 c^2}{3 d^2 x}-\frac{b^2 c^3 \tan ^{-1}(c x)}{d^2} \]
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Rubi [A] time = 0.963293, antiderivative size = 401, normalized size of antiderivative = 1., number of steps used = 32, number of rules used = 15, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.577, Rules used = {5747, 5690, 5693, 4180, 2531, 2282, 6589, 5717, 203, 5755, 5760, 4182, 2279, 2391, 325} \[ -\frac{5 i b c^3 \text{PolyLog}\left (2,-i e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{d^2}+\frac{5 i b c^3 \text{PolyLog}\left (2,i e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{d^2}+\frac{13 b^2 c^3 \text{PolyLog}\left (2,-e^{\sinh ^{-1}(c x)}\right )}{3 d^2}-\frac{13 b^2 c^3 \text{PolyLog}\left (2,e^{\sinh ^{-1}(c x)}\right )}{3 d^2}+\frac{5 i b^2 c^3 \text{PolyLog}\left (3,-i e^{\sinh ^{-1}(c x)}\right )}{d^2}-\frac{5 i b^2 c^3 \text{PolyLog}\left (3,i e^{\sinh ^{-1}(c x)}\right )}{d^2}+\frac{5 c^4 x \left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^2 \left (c^2 x^2+1\right )}+\frac{2 b c^3 \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 \sqrt{c^2 x^2+1}}+\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x \left (c^2 x^2+1\right )}-\frac{b c \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 x^2 \sqrt{c^2 x^2+1}}-\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x^3 \left (c^2 x^2+1\right )}+\frac{5 c^3 \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )^2}{d^2}+\frac{26 b c^3 \tanh ^{-1}\left (e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2}-\frac{b^2 c^2}{3 d^2 x}-\frac{b^2 c^3 \tan ^{-1}(c x)}{d^2} \]
Antiderivative was successfully verified.
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Rule 5747
Rule 5690
Rule 5693
Rule 4180
Rule 2531
Rule 2282
Rule 6589
Rule 5717
Rule 203
Rule 5755
Rule 5760
Rule 4182
Rule 2279
Rule 2391
Rule 325
Rubi steps
\begin{align*} \int \frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{x^4 \left (d+c^2 d x^2\right )^2} \, dx &=-\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x^3 \left (1+c^2 x^2\right )}-\frac{1}{3} \left (5 c^2\right ) \int \frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{x^2 \left (d+c^2 d x^2\right )^2} \, dx+\frac{(2 b c) \int \frac{a+b \sinh ^{-1}(c x)}{x^3 \left (1+c^2 x^2\right )^{3/2}} \, dx}{3 d^2}\\ &=-\frac{b c \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 x^2 \sqrt{1+c^2 x^2}}-\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x^3 \left (1+c^2 x^2\right )}+\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x \left (1+c^2 x^2\right )}+\left (5 c^4\right ) \int \frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{\left (d+c^2 d x^2\right )^2} \, dx+\frac{\left (b^2 c^2\right ) \int \frac{1}{x^2 \left (1+c^2 x^2\right )} \, dx}{3 d^2}-\frac{\left (b c^3\right ) \int \frac{a+b \sinh ^{-1}(c x)}{x \left (1+c^2 x^2\right )^{3/2}} \, dx}{d^2}-\frac{\left (10 b c^3\right ) \int \frac{a+b \sinh ^{-1}(c x)}{x \left (1+c^2 x^2\right )^{3/2}} \, dx}{3 d^2}\\ &=-\frac{b^2 c^2}{3 d^2 x}-\frac{13 b c^3 \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 \sqrt{1+c^2 x^2}}-\frac{b c \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 x^2 \sqrt{1+c^2 x^2}}-\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x^3 \left (1+c^2 x^2\right )}+\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x \left (1+c^2 x^2\right )}+\frac{5 c^4 x \left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^2 \left (1+c^2 x^2\right )}-\frac{\left (b c^3\right ) \int \frac{a+b \sinh ^{-1}(c x)}{x \sqrt{1+c^2 x^2}} \, dx}{d^2}-\frac{\left (10 b c^3\right ) \int \frac{a+b \sinh ^{-1}(c x)}{x \sqrt{1+c^2 x^2}} \, dx}{3 d^2}-\frac{\left (b^2 c^4\right ) \int \frac{1}{1+c^2 x^2} \, dx}{3 d^2}+\frac{\left (b^2 c^4\right ) \int \frac{1}{1+c^2 x^2} \, dx}{d^2}+\frac{\left (10 b^2 c^4\right ) \int \frac{1}{1+c^2 x^2} \, dx}{3 d^2}-\frac{\left (5 b c^5\right ) \int \frac{x \left (a+b \sinh ^{-1}(c x)\right )}{\left (1+c^2 x^2\right )^{3/2}} \, dx}{d^2}+\frac{\left (5 c^4\right ) \int \frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{d+c^2 d x^2} \, dx}{2 d}\\ &=-\frac{b^2 c^2}{3 d^2 x}+\frac{2 b c^3 \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 \sqrt{1+c^2 x^2}}-\frac{b c \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 x^2 \sqrt{1+c^2 x^2}}-\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x^3 \left (1+c^2 x^2\right )}+\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x \left (1+c^2 x^2\right )}+\frac{5 c^4 x \left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^2 \left (1+c^2 x^2\right )}+\frac{4 b^2 c^3 \tan ^{-1}(c x)}{d^2}+\frac{\left (5 c^3\right ) \operatorname{Subst}\left (\int (a+b x)^2 \text{sech}(x) \, dx,x,\sinh ^{-1}(c x)\right )}{2 d^2}-\frac{\left (b c^3\right ) \operatorname{Subst}\left (\int (a+b x) \text{csch}(x) \, dx,x,\sinh ^{-1}(c x)\right )}{d^2}-\frac{\left (10 b c^3\right ) \operatorname{Subst}\left (\int (a+b x) \text{csch}(x) \, dx,x,\sinh ^{-1}(c x)\right )}{3 d^2}-\frac{\left (5 b^2 c^4\right ) \int \frac{1}{1+c^2 x^2} \, dx}{d^2}\\ &=-\frac{b^2 c^2}{3 d^2 x}+\frac{2 b c^3 \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 \sqrt{1+c^2 x^2}}-\frac{b c \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 x^2 \sqrt{1+c^2 x^2}}-\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x^3 \left (1+c^2 x^2\right )}+\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x \left (1+c^2 x^2\right )}+\frac{5 c^4 x \left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^2 \left (1+c^2 x^2\right )}+\frac{5 c^3 \left (a+b \sinh ^{-1}(c x)\right )^2 \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{d^2}-\frac{b^2 c^3 \tan ^{-1}(c x)}{d^2}+\frac{26 b c^3 \left (a+b \sinh ^{-1}(c x)\right ) \tanh ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{3 d^2}-\frac{\left (5 i b c^3\right ) \operatorname{Subst}\left (\int (a+b x) \log \left (1-i e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{d^2}+\frac{\left (5 i b c^3\right ) \operatorname{Subst}\left (\int (a+b x) \log \left (1+i e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{d^2}+\frac{\left (b^2 c^3\right ) \operatorname{Subst}\left (\int \log \left (1-e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{d^2}-\frac{\left (b^2 c^3\right ) \operatorname{Subst}\left (\int \log \left (1+e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{d^2}+\frac{\left (10 b^2 c^3\right ) \operatorname{Subst}\left (\int \log \left (1-e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{3 d^2}-\frac{\left (10 b^2 c^3\right ) \operatorname{Subst}\left (\int \log \left (1+e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{3 d^2}\\ &=-\frac{b^2 c^2}{3 d^2 x}+\frac{2 b c^3 \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 \sqrt{1+c^2 x^2}}-\frac{b c \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 x^2 \sqrt{1+c^2 x^2}}-\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x^3 \left (1+c^2 x^2\right )}+\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x \left (1+c^2 x^2\right )}+\frac{5 c^4 x \left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^2 \left (1+c^2 x^2\right )}+\frac{5 c^3 \left (a+b \sinh ^{-1}(c x)\right )^2 \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{d^2}-\frac{b^2 c^3 \tan ^{-1}(c x)}{d^2}+\frac{26 b c^3 \left (a+b \sinh ^{-1}(c x)\right ) \tanh ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{3 d^2}-\frac{5 i b c^3 \left (a+b \sinh ^{-1}(c x)\right ) \text{Li}_2\left (-i e^{\sinh ^{-1}(c x)}\right )}{d^2}+\frac{5 i b c^3 \left (a+b \sinh ^{-1}(c x)\right ) \text{Li}_2\left (i e^{\sinh ^{-1}(c x)}\right )}{d^2}+\frac{\left (5 i b^2 c^3\right ) \operatorname{Subst}\left (\int \text{Li}_2\left (-i e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{d^2}-\frac{\left (5 i b^2 c^3\right ) \operatorname{Subst}\left (\int \text{Li}_2\left (i e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{d^2}+\frac{\left (b^2 c^3\right ) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{\sinh ^{-1}(c x)}\right )}{d^2}-\frac{\left (b^2 c^3\right ) \operatorname{Subst}\left (\int \frac{\log (1+x)}{x} \, dx,x,e^{\sinh ^{-1}(c x)}\right )}{d^2}+\frac{\left (10 b^2 c^3\right ) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{\sinh ^{-1}(c x)}\right )}{3 d^2}-\frac{\left (10 b^2 c^3\right ) \operatorname{Subst}\left (\int \frac{\log (1+x)}{x} \, dx,x,e^{\sinh ^{-1}(c x)}\right )}{3 d^2}\\ &=-\frac{b^2 c^2}{3 d^2 x}+\frac{2 b c^3 \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 \sqrt{1+c^2 x^2}}-\frac{b c \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 x^2 \sqrt{1+c^2 x^2}}-\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x^3 \left (1+c^2 x^2\right )}+\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x \left (1+c^2 x^2\right )}+\frac{5 c^4 x \left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^2 \left (1+c^2 x^2\right )}+\frac{5 c^3 \left (a+b \sinh ^{-1}(c x)\right )^2 \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{d^2}-\frac{b^2 c^3 \tan ^{-1}(c x)}{d^2}+\frac{26 b c^3 \left (a+b \sinh ^{-1}(c x)\right ) \tanh ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{3 d^2}+\frac{13 b^2 c^3 \text{Li}_2\left (-e^{\sinh ^{-1}(c x)}\right )}{3 d^2}-\frac{5 i b c^3 \left (a+b \sinh ^{-1}(c x)\right ) \text{Li}_2\left (-i e^{\sinh ^{-1}(c x)}\right )}{d^2}+\frac{5 i b c^3 \left (a+b \sinh ^{-1}(c x)\right ) \text{Li}_2\left (i e^{\sinh ^{-1}(c x)}\right )}{d^2}-\frac{13 b^2 c^3 \text{Li}_2\left (e^{\sinh ^{-1}(c x)}\right )}{3 d^2}+\frac{\left (5 i b^2 c^3\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(-i x)}{x} \, dx,x,e^{\sinh ^{-1}(c x)}\right )}{d^2}-\frac{\left (5 i b^2 c^3\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(i x)}{x} \, dx,x,e^{\sinh ^{-1}(c x)}\right )}{d^2}\\ &=-\frac{b^2 c^2}{3 d^2 x}+\frac{2 b c^3 \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 \sqrt{1+c^2 x^2}}-\frac{b c \left (a+b \sinh ^{-1}(c x)\right )}{3 d^2 x^2 \sqrt{1+c^2 x^2}}-\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x^3 \left (1+c^2 x^2\right )}+\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d^2 x \left (1+c^2 x^2\right )}+\frac{5 c^4 x \left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^2 \left (1+c^2 x^2\right )}+\frac{5 c^3 \left (a+b \sinh ^{-1}(c x)\right )^2 \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{d^2}-\frac{b^2 c^3 \tan ^{-1}(c x)}{d^2}+\frac{26 b c^3 \left (a+b \sinh ^{-1}(c x)\right ) \tanh ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{3 d^2}+\frac{13 b^2 c^3 \text{Li}_2\left (-e^{\sinh ^{-1}(c x)}\right )}{3 d^2}-\frac{5 i b c^3 \left (a+b \sinh ^{-1}(c x)\right ) \text{Li}_2\left (-i e^{\sinh ^{-1}(c x)}\right )}{d^2}+\frac{5 i b c^3 \left (a+b \sinh ^{-1}(c x)\right ) \text{Li}_2\left (i e^{\sinh ^{-1}(c x)}\right )}{d^2}-\frac{13 b^2 c^3 \text{Li}_2\left (e^{\sinh ^{-1}(c x)}\right )}{3 d^2}+\frac{5 i b^2 c^3 \text{Li}_3\left (-i e^{\sinh ^{-1}(c x)}\right )}{d^2}-\frac{5 i b^2 c^3 \text{Li}_3\left (i e^{\sinh ^{-1}(c x)}\right )}{d^2}\\ \end{align*}
Mathematica [A] time = 8.73125, size = 764, normalized size = 1.91 \[ \frac{2 a b \left (-\frac{5}{4} i c^4 \left (\frac{2 \text{PolyLog}\left (2,-i e^{\sinh ^{-1}(c x)}\right )}{c}-\frac{\sinh ^{-1}(c x)^2}{2 c}+\frac{2 \sinh ^{-1}(c x) \log \left (1+i e^{\sinh ^{-1}(c x)}\right )}{c}\right )+\frac{5}{4} i c^4 \left (\frac{2 \text{PolyLog}\left (2,i e^{\sinh ^{-1}(c x)}\right )}{c}-\frac{\sinh ^{-1}(c x)^2}{2 c}+\frac{2 \sinh ^{-1}(c x) \log \left (1-i e^{\sinh ^{-1}(c x)}\right )}{c}\right )-\frac{c \sqrt{c^2 x^2+1}}{6 x^2}+\frac{c^4 \left (\sinh ^{-1}(c x)+i \sqrt{c^2 x^2+1}\right )}{4 \left (c^2 x+i c\right )}-\frac{c^3 \left (\sqrt{c^2 x^2+1}+i \sinh ^{-1}(c x)\right )}{4 (-1-i c x)}+\frac{1}{6} c^3 \tanh ^{-1}\left (\sqrt{c^2 x^2+1}\right )-2 c^2 \left (-c \tanh ^{-1}\left (\sqrt{c^2 x^2+1}\right )-\frac{\sinh ^{-1}(c x)}{x}\right )-\frac{\sinh ^{-1}(c x)}{3 x^3}\right )}{d^2}+\frac{b^2 c^3 \left (-104 \text{PolyLog}\left (2,-e^{-\sinh ^{-1}(c x)}\right )-120 i \sinh ^{-1}(c x) \text{PolyLog}\left (2,-i e^{-\sinh ^{-1}(c x)}\right )+120 i \sinh ^{-1}(c x) \text{PolyLog}\left (2,i e^{-\sinh ^{-1}(c x)}\right )+104 \text{PolyLog}\left (2,e^{-\sinh ^{-1}(c x)}\right )-120 i \text{PolyLog}\left (3,-i e^{-\sinh ^{-1}(c x)}\right )+120 i \text{PolyLog}\left (3,i e^{-\sinh ^{-1}(c x)}\right )-\frac{8 \sinh ^{-1}(c x)^2 \sinh ^4\left (\frac{1}{2} \sinh ^{-1}(c x)\right )}{c^3 x^3}+\frac{12 c x \sinh ^{-1}(c x)^2}{c^2 x^2+1}+\frac{24 \sinh ^{-1}(c x)}{\sqrt{c^2 x^2+1}}-104 \sinh ^{-1}(c x) \log \left (1-e^{-\sinh ^{-1}(c x)}\right )-60 i \sinh ^{-1}(c x)^2 \log \left (1-i e^{-\sinh ^{-1}(c x)}\right )+60 i \sinh ^{-1}(c x)^2 \log \left (1+i e^{-\sinh ^{-1}(c x)}\right )+104 \sinh ^{-1}(c x) \log \left (e^{-\sinh ^{-1}(c x)}+1\right )-26 \sinh ^{-1}(c x)^2 \tanh \left (\frac{1}{2} \sinh ^{-1}(c x)\right )+4 \tanh \left (\frac{1}{2} \sinh ^{-1}(c x)\right )+26 \sinh ^{-1}(c x)^2 \coth \left (\frac{1}{2} \sinh ^{-1}(c x)\right )-4 \coth \left (\frac{1}{2} \sinh ^{-1}(c x)\right )-\frac{1}{2} c x \sinh ^{-1}(c x)^2 \text{csch}^4\left (\frac{1}{2} \sinh ^{-1}(c x)\right )-2 \sinh ^{-1}(c x) \text{csch}^2\left (\frac{1}{2} \sinh ^{-1}(c x)\right )-2 \sinh ^{-1}(c x) \text{sech}^2\left (\frac{1}{2} \sinh ^{-1}(c x)\right )-48 \tan ^{-1}\left (\tanh \left (\frac{1}{2} \sinh ^{-1}(c x)\right )\right )\right )}{24 d^2}+\frac{a^2 c^4 x}{2 d^2 \left (c^2 x^2+1\right )}+\frac{2 a^2 c^2}{d^2 x}+\frac{5 a^2 c^3 \tan ^{-1}(c x)}{2 d^2}-\frac{a^2}{3 d^2 x^3} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.338, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( a+b{\it Arcsinh} \left ( cx \right ) \right ) ^{2}}{{x}^{4} \left ({c}^{2}d{x}^{2}+d \right ) ^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{6} \,{\left (\frac{15 \, c^{3} \arctan \left (c x\right )}{d^{2}} + \frac{15 \, c^{4} x^{4} + 10 \, c^{2} x^{2} - 2}{c^{2} d^{2} x^{5} + d^{2} x^{3}}\right )} a^{2} + \int \frac{b^{2} \log \left (c x + \sqrt{c^{2} x^{2} + 1}\right )^{2}}{c^{4} d^{2} x^{8} + 2 \, c^{2} d^{2} x^{6} + d^{2} x^{4}} + \frac{2 \, a b \log \left (c x + \sqrt{c^{2} x^{2} + 1}\right )}{c^{4} d^{2} x^{8} + 2 \, c^{2} d^{2} x^{6} + d^{2} x^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b^{2} \operatorname{arsinh}\left (c x\right )^{2} + 2 \, a b \operatorname{arsinh}\left (c x\right ) + a^{2}}{c^{4} d^{2} x^{8} + 2 \, c^{2} d^{2} x^{6} + d^{2} x^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{a^{2}}{c^{4} x^{8} + 2 c^{2} x^{6} + x^{4}}\, dx + \int \frac{b^{2} \operatorname{asinh}^{2}{\left (c x \right )}}{c^{4} x^{8} + 2 c^{2} x^{6} + x^{4}}\, dx + \int \frac{2 a b \operatorname{asinh}{\left (c x \right )}}{c^{4} x^{8} + 2 c^{2} x^{6} + x^{4}}\, dx}{d^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \operatorname{arsinh}\left (c x\right ) + a\right )}^{2}}{{\left (c^{2} d x^{2} + d\right )}^{2} x^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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